(8c24p21&95) The ammonia molecule NH3 has a permanent electric dipole moment equ

Question

(8c24p21&95) The ammonia molecule NH3 has a permanent electric dipole moment equal to 1.47D, where 1D = debye unit = 3.34×10-30 C* m. a) Calculate the electric potential due to an ammonia molecule at a point 52 nm away along the axis of the dipole. (Set V = 0 at infinity.) - I figured out this part but i cant get part B.
Answer for part a) 1.63x10^-5V

b) (c24p107) Starting from Eq. 25-30, find the electric field due to a dipole at a point on the dipole axis. Calculate the electric field due to an ammonia molecule at a point 52 nm away along the axis of the dipole.

Explanation / Answer

The electric potential due to an ammonia molecule at a point r = 52 nm away along the axis of the dipole is V = k * (p/r2) where k = (1/4o) = 9 * 109 Nm2/C2,p = 1.47D = 1.47 * 3.34 * 10-30 C* m = 4.9 * 10-30 C* m and r = 52 nm = 52 * 10-9 m The electric field along the axis of the dipole is Edipole = k * (p/r3)

Related Questions

Navigate

• Browse (All)
• Browse #
• Subjects

---