A proton moving with a spweed of 3 x 10 5 m/s perpendicular to a uniform magneti

Question

A proton moving with a spweed of 3 x 10 5  m/s perpendicular to a uniform magnetic field 0.20 T will follow which of the paths described below (q p=1.6 x 1019 C and mp    = 1.67 x 10 27 kg)   
a. a straight line path b. a circular path of 1.5 cm radius c. a circular path of 3.0 cm radius d. a circular path of 0.75 cm radius         A proton moving with a spweed of 3 x 10 5  m/s perpendicular to a uniform magnetic field 0.20 T will follow which of the paths described below (q p=1.6 x 1019 C and mp    = 1.67 x 10 27 kg)   
a. a straight line path b. a circular path of 1.5 cm radius c. a circular path of 3.0 cm radius d. a circular path of 0.75 cm radius        

Explanation / Answer

We know that    mv^2/r = Bqv    r = mv/(Bq)      = (1.67 x 10 27 kg)(3 x 10 5  m/s)/((0.20 T)(1.6 x 1019 C))      = 0.01565625 m      = 1.56 cm circular path.

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