1. Two people are pulling horizontally on the opposite ends of a 5.0 kg box. If

Question

1. Two people are pulling horizontally on the opposite ends of a 5.0 kg box. If the person on the right pulls with a force of 12 N, what is the other force if the box accelerates to the right at 2.0 m/s^2?

2. Tom who weighs 490 N stands on a "bathroom-type scale" in an elevator. What does the scale read if he accelerates upward at 2.0 m/s^2?

3. After a traffic accident, it is determined that a car's skid marks are 125 m long. The coefficient of friction between the car's tires and the roadway were found to be 0.50 for the road conditions. Determine the velocity of the car when the brakes were first applied.


I would also like to see how the problem is solved. Thank you :D

Explanation / Answer

1) mass of the box m =5kg accelertion to right a = 2m/s^2 net force to right F = ma = 10N right side force F1 =12N other side force F2 = F1-F = 12N-10N=2N. 2)weight of Tom w =490N mass of Tom m = w/g = 490/9.8 =50kg acceleration of elevator a=2m/s^2 scale reading w1 = m(g+a) w1=50*(9.8+2)N w1=590N. 3)the distance traveled before accident s =125m coefficent of friction µ=0.5 acceleration a =µg =0.5*9.8=4.9m/s^2 final velocity vf=0 intial velocity vi =? from(vf)2=(vi)2+2as (vi)2=-2(-4.9)*125 vi=35m/s

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