I need help with the question listed above. The answer is included. I need help

Question

I need help with the question listed above. The answer is included. I need help solving the problem so I can get the correct answer. Please show a detailed explanation. I need help with the question listed above. The answer is included. I need help solving the problem so I can get the correct answer. Please show a detailed explanation.

Explanation / Answer

P 14. The net force acting on the sides of length is F = i L X B In this case the B is parallel to L so that @ = 0 ==> F1 = F2 = i L B sin@ = i L B sin0 = 0 N Therefore the net magnetic force acting on the wire of length 2L is F3 = i 2L B sin90 = 2iLB Therefore the total force acting on the wire F = F1 + F2 + F3 = 0 + 0+ 2iLB = 2i L B P 15. radius r = m v / qB Given that B = 0.8 T K = 3.0 k eV = 3000 x 1.602 x 10^-19 J = 4.806 x 10^-16 J m = 1.67 x 10^-27 kg q = 1.6 x 10^-19 C Therefore radius can be written as r = [2mK]^1/2 / qB = [2 * 1.67 x 10^-27 * 4.806 x 10-16]^1/2 / 1.6 x 10^-19 * 0.8 = 0.09898 m

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