In the figure below, two particles are launched from the origin of the coordinat
ID: 1697222 • Letter: I
Question
In the figure below, two particles are launched from the origin of the coordinate system at time t = 0. Particle 1 of mass m1 = 5.00 g is shot directly along an x axis (on a frictionless floor), where it moves with a constant speed of 20.0 m/s. Particle 2 of mass m2 = 3.00 g is shot with a velocity of magnitude 40.0 m/s, at an upward angle such that it always stays directly above particle 1 during its flight.Chapter 9 Problem 14
The cramster solution divides 300 by 19.3. Where do these figures come from. Please advise
Explanation / Answer
Both particles are vertically aligned Here V2x = V1 = 10 m/s Initial value of V2 is 20 m/s Hence, V2y = sqrt ( V2 ^ 2 - V2x ^ 2 ) = sqrt ( 20 ^ 2 - 10 ^ 2 ) = sqrt (300) m/s From the equ. of motion, V ^2 - U ^ 2 = 2 a s V2y ^ 2 - 0 = 2 * g * Ymax 300 - 0 = 2 * 9.8 * Ymax So, Ymax = 300 / 19.6