Here\'s a fun (but FAKED) video about projectile motion on YouTube (http://www.y
ID: 1707515 • Letter: H
Question
Here's a fun (but FAKED) video about projectile motion on YouTube (http://www.youtube.com/watch?v=vBvUBQWK0w4)Just for fun, let's pretend that it was real. Use a launch angle of 42 degrees and assume that the landing height is the same as the launch height. Do not assume the time shown in the video is to be trusted (though you can compare your calculate to it afterwards). Use the 150 feet value for the distance between ramp and landing site (the pool) to figure out:
(a) time in the air (calculated)
(b) launch speed from ramp m/s
(c) landing speed in pool (in miles/hour) MPH
(d) max height above the ground (assume ground is flat and ignore height of ramp) m
Explanation / Answer
a) assume initial velocity to be v. we have v*cos 42*t=150(feet)=45.7(m) 2v*sin42/g=t. so we have v^2*2*sin42*cos42/g=45.7 so v=21.2(m/s). so t=2.9(s). b). v=21.2(m/s). c) its 21.2(m/s)=6.5(miles) d) max speed is equal to initial (or final) speed of 21.2(m/s_