For the 16\" times 16\" (15.625\" times 15.625\" actual) pilaster, construct an

Question

For the 16" times 16" (15.625" times 15.625" actual) pilaster, construct an approximate Strength Design P-M diagram and evaluate whether the given demand pairs are acceptable. h = 20 feet, 1d = 3" (4) #6 vertical bars, one per corner, fy = 60ksi Masonry compressive strength fm 2000 psi solid grouted Lateral ties meet code requirements for confinement Calculate the flexural capacity with no axial load assuming singly reinforced (tension steel only) at P-M diagram Point #3 Approximately Envelope List P-M Curve Point Coordinates:

Explanation / Answer

As mentioned Size (16” X 16”) (15.625” X 15.625”)

H= 20 feet

D= 13”

6 mm dia bar

4 in numbers , fy= 60Ksi

Masonry Compressive Strength = f’m = 2000 psi

Calculate flexular capacity

Puz = 0.45 fck Ac + 0.75 fy Asc

Ac= Ag - Asc

Ag = (15.625 x 15.625) in2 =244.14 in2

Asc= (3.14 x 0.02^2)X4 = 0.005024 in2

Ac = 244.135 in2

Pu = ((0.45 x 2x244.135) +(0.75 x 60 x 0.005024)

219.9475 K

We have Pu/fckbD = 0.54 and p/fck = 0.07538 i. Now, we get Mux1/fckbD2 from chart corresponding to d' = 13”,

Mux1/fckbD2 = 0.0378 = 199.63 k-ft

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