The details of an embankment made of cohesive soil with pu-0 and Cu-20 kPa are s
ID: 1713095 • Letter: T
Question
The details of an embankment made of cohesive soil with pu-0 and Cu-20 kPa are shown in Figure 1. The unit weight of the soil is 19 kN/m3. The weight of the sliding sector is 346 kN acting at an eccentricity of 5 m from the centre of rotation. It is assumed that no tension cracks developed. For the trial circle shown, determine the factor of safety against sliding for the following conditions: (i) The full embankment. (ii) The shaded portion of the embankment is removed 70° R=9m e=5m 3 m 1.5 m 1.1 3 m Figure 1Explanation / Answer
Given,
Weight of sector=346Kn
cu= 20 Kpa
Unit weight of soil = 19kN/m3
Radius r= 9m
Eccentricity e = 5
1. Factor of safety for the full embackment:
Disturbing moment= Wight of sector x Eccentricity
= 346 x 5
= 1730 kNm
Restraining moment= cur2
= 20 x 92 x 70/180 x 3.14
= 1980 kNm
Factor of safety = Restraining moment/ Disturbing moment
= 1980/1730
= 1.14
2. Factor of safety for shaded portion of the slope is removed
Area of portion removed = 1.5 x 3 = 4.5 m2
Weight removed = 4.5 x 19 = 85.5 kN
Eccentricity from O = 3.3+ (3.3+1.5)/2 = 5.7 m
Relief from disturbing moment = 5.7 x 85.5 = 490 kNm
Factor of safety = 1980/(1730-490)
= 1.6