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Please make sure you use the right dimensions and make sure you use the right fo

ID: 1713476 • Letter: P

Question

Please make sure you use the right dimensions and make sure you use the right formulas!! Check you work! Thanks!

3. For the floor plan shown below, design members B1 and G1 for bending, shear and deflection. Compare deflections with L/240 for total loads and L/360 for live loads. The steel is ASTM A992., Grade 50; you may assume that Cb-1.0 for bending. The dead load (including the beam weight) is assumed to be 85 psf and the live load is 150 psf. Assume that the floor deck proveds full lateral stability to the top flange of B1. Ignore live load reduction. Use the design tables in the AISCM where appropriate. Remember to check any assumptions you make. 1 6'-8 G1 6'-8" 6'-8 30'-0" 30-0"

Explanation / Answer

Design of B1:

Tributary width =6'8"=6.67 feet

Dead load on beam = 85*6.67=566.67 plf=0.5667 kip/ft

live load on beam = 150*6.67=1000 plf=1 kip/ft

design moment on beam = (1.2*0.5667*302/8)+(1.6*1*302/8)=256.5 kip-ft

Design shear force on beam = (1.2*0.5667*30/2)+(1.6*1*30/2) = 34.2 kips

Use W16x40

Moment capapcity of beam = 274 kip-ft

Shear capapcity of beam = 146 kips

Moment of inertia of beam = 518 in4

Deflection of beam due to total load = [(5*(0.5667+1)/12)*(30*12)4]/(384*29000*518) = 1.9 in

L/240 = 30*12/240=1.5 in

Let us provide a stiffer beam

Let us consider W21x44

Moment of inertia=843 in4

Total deflection of beam = [(5*(0.5667+1)/12)*(30*12)4]/(384*29000*843)=1.17 in(<1.5 in)

deflection of beam due to live load = [(5*1/12)*(30*12)4]/(384*29000*843)=0.745 in

L/360 = 360/360=1 in

Therefore the deflection is also within limit

provide W21x44 as B1

Design of G1 :

The girder is subjected to concentrated force coming from 4-B1 beams supported on it

Factored concentrated force coming on girder from each B1 =34.2 kips

Maximum shear force in girder = 4*34.2/2=68.4 kips

Maximum moment in girder = 68.4*6.67=456 kip-ft

Let us consider W24x55

Moment capacity of beam for unbraced length of 6.67 ft = 460 kip-ft

Shear force capacity of beam = 252 kips

Deflection check:

service level dead load on girder from each beam B1 = 0.5667*15=8.5 kips

service level live load on girder from each beam B1=1*15=15 kips

Moment of inertia of W24x55 = 1350 in4

Deflection of beam due to total load = (23/648)*(30+17)*(20*12)3/(29000*1350)=0.589 in

L/240 = 20*12/240=1 in

deflection of girder due to live load = (23/648)*(30)*(20*12)3/(29000*1350)=0.376 in

L/360 = (20*12)/360=0.67 in

Let us provide W24x55 as girder