An internal explosion breaks an object, initially at rest,into two pieces, one o

Question

An internal explosion breaks an object, initially at rest,into two pieces, one of which has 1.42 times the mass of the other.If 7540 J were released in the explosion, how much kinetic energydid the heavier piece acquire?
How much KE did the lighter piece acquire? I tried solving this with a proportion but to no avail.. An internal explosion breaks an object, initially at rest,into two pieces, one of which has 1.42 times the mass of the other.If 7540 J were released in the explosion, how much kinetic energydid the heavier piece acquire?
How much KE did the lighter piece acquire? I tried solving this with a proportion but to no avail..

Explanation / Answer

Well you forgot to include momentum maintaining momentum because itis an internal explosion thus internal force Pi=Pf 0=MV+mv where M is the mass of the larger object and m the mass ofthe smaller 0=m(1.42V+v) v=-1.42V now you have a more interesting proportionality as the velocity ofthe second is 1.42 times larger than the other, which is squaredwhile the other only has 1.42 times more mass, so the smallerobject has 1.42 times more energy.

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