A circular-motion addict of mass 85 kgrides a Ferris wheel around in a vertical

Question

A circular-motion addict of mass 85 kgrides a Ferris wheel around in a vertical circle of radius 10 m ata constant speed of 6.1 m/s. (a) What is the period of the motion?
1 s

(b) What is the magnitude of the normal force on the addict fromthe seat when both go through the highest point of the circularpath?
2 N

(c) What is it when both go through the lowest point?
3 N (a) What is the period of the motion?
1 s

(b) What is the magnitude of the normal force on the addict fromthe seat when both go through the highest point of the circularpath?
2 N

(c) What is it when both go through the lowest point?
3 N

Explanation / Answer

   Mass, M = 70 kg    Radius, R = 10 m       Linear Speed, V = 6 m/s    Angular speed, = V / R = 6 / 10 = 0.6rad / s     (a)    Time period, T = 2 /                           =2 * 3.14 / 0.6                          = 10.47 s (b)     Normal Force at the highest point , N = (MV2 / R ) - M g                                                              =( 70 * 36 / 10 ) - 70 * 9.8                                                              =252 - 686                                                             = -434 N (c)    normal force at the lowest point, N = (MV2 / R )  + M g                                                              =( 70 * 36 / 10 ) + 70 * 9.8                                                              =252 + 686                                                             = 938 N                                                              =( 70 * 36 / 10 ) + 70 * 9.8                                                              =252 + 686                                                             = 938 N

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