I only need help with part d. Thanks. A 0.060-kg handball is thrown straight tow

Question

I only need help with part d. Thanks. A 0.060-kg handball is thrown straight toward a wall with aspeed of 10 m/s. It rebounds straightbackward at a speed of 8.5 m/s. (a) What impulse is exerted on the wall?
1.11 kgm/s
(b) If the ball is in contact with the wall for 3.0 ms, whataverage force is exerted on the wall by the ball?
370 N

(c) The rebounding ball is caught by a player who brings it torest. During the process, her hand moves back 0.40 m. What is the impulse received by theplayer?
.51Ns
(d) What average force was exerted on the player by the ball?
? N I only need help with part d. Thanks. A 0.060-kg handball is thrown straight toward a wall with aspeed of 10 m/s. It rebounds straightbackward at a speed of 8.5 m/s. (a) What impulse is exerted on the wall?
1.11 kgm/s
(b) If the ball is in contact with the wall for 3.0 ms, whataverage force is exerted on the wall by the ball?
370 N

(c) The rebounding ball is caught by a player who brings it torest. During the process, her hand moves back 0.40 m. What is the impulse received by theplayer?
.51Ns
(d) What average force was exerted on the player by the ball?
? N

Explanation / Answer

You could approach it from a work/energy perspective. W = Favg x KE = 0.5mv2 Favg = 0.5mv2/x = 0.5(0.06 kg)(8.5m/s)2/0.4m = 5.4N Favg = 0.5mv2/x = 0.5(0.06 kg)(8.5m/s)2/0.4m = 5.4N

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