A CD has a mass of 17 g and a radius of 6.0 cm. When insertedinto a player, the

Question

A CD has a mass of 17 g and a radius of 6.0 cm. When insertedinto a player, the CD starts from rest and accelerates to anangular velocity of 21 rad/s in0.70 s. Assuming the CD is a uniformsolid disk, determine the net torque acting on it.
-I tried to get moment of inertia by mr^2 and got .0000612,then I got my angular acceleration = 30 rad/s^2. Multiplyingthese two I got Torque = 0.001836 N x m What am I doing wrong? A CD has a mass of 17 g and a radius of 6.0 cm. When insertedinto a player, the CD starts from rest and accelerates to anangular velocity of 21 rad/s in0.70 s. Assuming the CD is a uniformsolid disk, determine the net torque acting on it.
-I tried to get moment of inertia by mr^2 and got .0000612,then I got my angular acceleration = 30 rad/s^2. Multiplyingthese two I got Torque = 0.001836 N x m What am I doing wrong?

Explanation / Answer

For soild disk moment of inertia I = ( 1/ 2) m r ^ 2                                                    =( 1/ 2) * ( 17 / 1000) kg * ( 6 /100) ^ 2                                                   = 306*10 ^ -7 kg m ^ 2 angulae accleration = 21 rad / s / 0.7 s                                 =30 rad / s ^ 2 So, torque = I = 9.18 * 10 ^ -4 N m

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