I know the answer, I just do not know how you math it. Twoautos are equipped wit
ID: 1724844 • Letter: I
Question
I know the answer, I just do not know how you math it. Twoautos are equipped with the same single-frequency horn. When one isat rest and the other is moving toward the first at 15 m/s, thedriver at rest hears a beat frequency of 5.5 Hz. What is thefrequency the horns emit? Assume T = 20oC. I get 5.5 = 1.04 f 1 - f 1 Do I experiment by multiplying-say 150 by 1.04 and thensubtract 150 and see how close I am to 5.5 and when I finally getit to match it is correct? Or is there a simpler way backing up 343/343-15 was how I got 1.04. The answer is 120Hz. I know the answer, I just do not know how you math it. Twoautos are equipped with the same single-frequency horn. When one isat rest and the other is moving toward the first at 15 m/s, thedriver at rest hears a beat frequency of 5.5 Hz. What is thefrequency the horns emit? Assume T = 20oC. I get 5.5 = 1.04 f 1 - f 1 Do I experiment by multiplying-say 150 by 1.04 and thensubtract 150 and see how close I am to 5.5 and when I finally getit to match it is correct? Or is there a simpler way backing up 343/343-15 was how I got 1.04. The answer is 120Hz.Explanation / Answer
Two autos are equipped with the same single-frequencyhorn. When one is at rest and the other is moving toward the firstat 15 m/s, the driver at rest hears a beat frequency of 5.5 Hz.What is the frequency the horns emit? Assume T = 20oC. I get 5.5 = 1.04 f 1 - f 1 Do I experiment by multiplying-say 150 by 1.04 and thensubtract 150 and see how close I am to 5.5 and when I finally getit to match it is correct? Or is there a simpler way backing up 343/343-15 was how I got 1.04. The answer is 120Hz.velocity of sound at 20 degree=342m/sec
let original frequency=n
changed frequency=n'=(342)n/342-15=1.045n
now beat frequency=(1.045-1)n=5.5
so n=122.22
hence the answer is 122which is nearer to the answer .