Captain Omega of the Imperial Space Patrol is in his Starcruiser,which is in a c

Question

Captain Omega of the Imperial Space Patrol is in his Starcruiser,which is in a circular orbit around the mysterious Planet X.Sensors indicate that the planet has a radius of 6640 km, and the Starcruiser is orbitting at analtitude of 1400 km above theplanet's surface. The ship completes one orbit in 3.8 hours.

(a) What is the orbital speed of the Starcruiser?
(b) What is the mass of Planet X?
(c) What would be the period of the Starcruiser's orbit if it wereto triple its altitude above theplanet's surface?

Explanation / Answer

The square of period of revolution isdirectly proportional to the cube of the distance of t hesatellite from the planet.
   T2 R3
So
   T22 /T12 = R23 /R13   
   Here R1 = 6640+1400 = 8040km =8040000m
   R2 = 6640 +3(1400) = 10840000m
  on putting the values
       T22 / (3.8 hr)2 = ( 10840000)3 /(8040000)3
   T2 =5.9489hr   

     
So
   T22 /T12 = R23 /R13   
   Here R1 = 6640+1400 = 8040km =8040000m
   R2 = 6640 +3(1400) = 10840000m
  on putting the values
       T22 / (3.8 hr)2 = ( 10840000)3 /(8040000)3
   T2 =5.9489hr   

     

Related Questions

Navigate

• Browse (All)
• Browse C
• Subjects

---