2. A football is kicked ( at ground level) at an angle of 37degrees with a veloc

Question

2. A football is kicked ( at ground level) at an angle of 37degrees with a velocity of 20 m/s

Calculate:

The max. height

the time of travel until it hits the ground.

how far away does it travel

the velocity vector at max height

the acceleration at max height

If the player wants to make a field goal, and the goal posts are30m away, will the ball pass over the 5m horizontal post?

b) Suposse the player " punts the ball, not from the groundbut at 1m high ( holding the ball with his hands)

How far did the ball travel before hitting the ground?

Explanation / Answer

   Given     1)   initial velocity of thefoot ball u = 20 m/s         angle ofprojectile         = 37 degrees a) maximum height    H = u2sin2    / 2 g                                     = (20) 2 sin2 37   / 2*9.8                                     = 7.3914 m b) time    t = 2 u sin /g                   = 2 x 20 x sin 37 / 9.8                   = 2.4563 s c)   Horizontal range   R =u2 sin 2 / g                                      = (20)2 ( sin 2x 37 )  / 9.8                                                                             = 39.2351 m d)   Velocity at maximumheight   v2 - u2 = 2gH           v2 = (20)2 + 2 x 9.8 x 7.3914               v= 23.3424 m/s e) Acceleration at maximum height              h = ut + (1/2 ) at2            7.3914=( 23.3424 ) (1.2281) + 0.5 x ax(1.2281)2                   a = -28.2122 m/s2            here negative sign represents opposite direction 2)   range   = ut                 = u 2 h / g                 =   (23.2434 )2 x 1 / 9.8                  = 10.5 m

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