In experiment 1, unpolarized light falls on the polarizer in thefigure below. Th
ID: 1725713 • Letter: I
Question
In experiment 1, unpolarized light falls on the polarizer in thefigure below. The angle of the analyzer is =69.3°. In experiment 2, theunpolarized light is replaced by light of the same intensity, butthe light is polarized along the direction of the polarizer'stransmission axis. By how many additional degrees must theanalyzer be rotated so that the light falling on the photocell willhave the same intensity as it did in experiment 1? Explain whether is increased or deceased by this additionalrotation. (Use a positive number to indicate an increase in theangle. Use a negative number to indicate a decrease in theangle.)Explanation / Answer
given that Angle ( ) =69.3o, Initial intensity = I In experiment 1, The intensity on the photocell = I1 = ( I/2)*cos2 In experiment 2, The intensity on the photocell = I2 =I*cos2' = (I/2)*cos2 cos2' = (1/2)*cos2 =0.06247 cos' = 0.2499 / = cos-1 (0.2499 ) ' = 75.5o additional angle = 75.5 - 69.3 = +6.2o