Alright, here goes: A frozen chicken is thrown by a teacher a distance of 47 met

Question

Alright, here goes:

A frozen chicken is thrown by a teacher a distance of 47 meters.According to a student looking at video analysis of the throw, thechicken initially traveled at an angle of 37 degrees up from thehorizontal. What height did the chicken reach? What was the initialvelocity? How long was it in flight?

I'm having a ton of trouble with soh cah toa. I'm also havingtrouble figuring out which equation to use and why. If I could geta step-by-step breakdown that would be wonderful. I'm slow withthis and I need someone to hold my hand down physics lane! Thankyou.

Explanation / Answer

let the init speed be v, we have: vx = vcos(37), vy = vsin(37) the time of travel is: t= 2vy/g = 2vsin(37)/g the distance D = 47m = vx*t =vcos(37)*2vsin(37)/g = v2 sin(2*37)/g v = [47m*9.8m/s2/sin(74)] = 21.89 m/s the max height h = vy2 / g =(vsin(37))2/g = [(21.89m/s*sin(37))2]/9.8m/s2 = 17.71 m height did the chicken reach is 17.71 m the initial velocity is vx = 21.89 m/s*cos(37) = 17.48m/s vy = 21.89m/s*sin(37) = 13.17m/s let time of flight be t, we have: t = 2vsin(37)/g = 2*21.89m/s *sin(37)/9.8m/s2 =2.69 s

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