A 220 g block hangs from a spring with spring constant16 N/m. At t=0 the block i

Question

A 220 g block hangs from a spring with spring constant16 N/m. At t=0 the block is 18 cm below the equilibriumpoint and moving upward with a speed of 122 cm/s. What are theblock's....

a) oscillation frequency?

b) distance from equilibrium when the speed is72 cm/s?
c) position at t=5 s? A 220 g block hangs from a spring with spring constant16 N/m. At t=0 the block is 18 cm below the equilibriumpoint and moving upward with a speed of 122 cm/s. What are theblock's....

a) oscillation frequency?

b) distance from equilibrium when the speed is72 cm/s?
c) position at t=5 s?

Explanation / Answer

   angularfrequency      =   (k/m)   =   (16/0.220)   =   8.258   rad/s    a.   Frequency   f   =   /2   =   8.258/ 2 *3.14   =   1.31   Hz    b.      speed   v2   =   2* ( A2   - y2 )          at   y   =   18cm            v18   =   1222   =   8.2582*(A2   -   182)          A2   =   (1222/8.2582)   +   182   =   542.26   =>   amplitude   A   =   542.26   =   23.28   cm            at   v   =   72   cm             722   =   8.2582* (542.26 - y2)          y   =   21.59   cm    c.   position   y   =   A* sin * t   =   23.28 * sin(8.258 *5)   =   -10.11   cm

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