A heat engine performs the reversible cycle abca with9.0 moles of an ideal gas. Path ca is an adiabaticprocess. The temperatures at points aand b are 300 K and 500 K, respectively. Thevolume at point c is 0.20 m^3. The adiabatic constant of thegas is 1.60. The work done by the gas in path ab, inkJ is? A heat engine performs the reversible cycle abca with9.0 moles of an ideal gas. Path ca is an adiabaticprocess. The temperatures at points aand b are 300 K and 500 K, respectively. Thevolume at point c is 0.20 m^3. The adiabatic constant of thegas is 1.60. The work done by the gas in path ab, inkJ is?
Explanation / Answer
The work done by the gas in path ab is W = P dV for ideal gas PV = nRT PdV+VdP =nRdT at constant pressure PdV = nRdT since dP =0 So, work done W =nRdT =(9 moles) ( 8.314 J / mol -K ) ( 500K - 300K ) = 14965.2 J