(a) What is the magnitude and direction of theimpulse imparted to the ball? magn

Question

(a) What is the magnitude and direction of theimpulse imparted to the ball? magnitude 1 kg · m/s direction 2°counterclockwise from the +x-axis
(b) If the ball (m = 0.147 kg)and bat are in contact for a time of 7.8ms, what is the magnitude of the average force of the bat on theball?
3 N

Compare this answer to the weight of the ball.
The contact force is 4 timesthe ball's weight.

(c) What is the impulse imparted to the bat?
magnitude 5 kg · m/s direction 6°counterclockwise from the +x-axis magnitude 1 kg · m/s direction 2°counterclockwise from the +x-axis

Explanation / Answer

.       Initial velocity (vi ) = 39 i m /s .       Final velocity (vf ) = 54 cos45 i + 54 sin45 j .          = 38.18 i + 38.18 j . (a) Momentum is : P = m( vf  - vi ) = 0.147 ( 38.18 i + 38.18 j -   39 i ) .             = -0.120 i + 5.61 j .    Magnitude is : sqrt [(-0.120)2  + (5.61)2  ] = 5.6 kg -m/s .    Direction is : = tan-1 ( 5.61 / -0.120) = ----- degree . (b) Average force exerted is : .    F = P / t = 5.6 / ( 7.8 * 10-3 ) = ---------- N . (c)   Weight of the ball is : m g = 0.147 * 9.8 = 1.4406 .    Hence contact force is 3.88 times the ball's weight. . (d) Impulse imparted on bat is equal inmagnitude but opposite in direction. .    Tins is from Newton'sthird law. . Hope this helps u!

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