A 32 kg skier skis directly down a frictionless slope angledat 12° to the horizontal. Choose the positive direction of thex axis to be downhill along the slope. A wind force withcomponent Fx acts on the skier. What isFx if the magnitude of the skier's velocity is(a) constant, (b) increasing at a rate of 1.4 m/s2, and(c) increasing at a rate of 2.8 m/s2. Part C was the only part that I got right and I followedcramster.... A 32 kg skier skis directly down a frictionless slope angledat 12° to the horizontal. Choose the positive direction of thex axis to be downhill along the slope. A wind force withcomponent Fx acts on the skier. What isFx if the magnitude of the skier's velocity is(a) constant, (b) increasing at a rate of 1.4 m/s2, and(c) increasing at a rate of 2.8 m/s2. Part C was the only part that I got right and I followedcramster....
Explanation / Answer
force down the slope + force up the slope = m a . mg sin12 +Fx = m a . Fx = - mgsin12 + ma for all threeparts . (a) Fx = - 32 * 9.80 *sin12 + 32 * 0 = - 65.20 Newtons . (b) Fx = -32 * 9.80 * sin12 + 32* 1.4 = - 20.40newtons . (c) Fx = -32 * 9.80 *sin12 + 32 * 2.8 = 24.40 Newtons watch the signs...