An indestructible bullet 2.00 cm long is fired straight through aboard that is 1

Question

An indestructible bullet 2.00 cm long is fired straight through aboard that is 10.0 cm thick. The bullet strikes the board with aspeed of 430 m/s and emerges with a speedof 275 m/s. (To simplify, assume that thebullet accelerates only while the front tip is in contact with thewood.) (a) What is the average acceleration of thebullet through the board?
1 m/s2
(b) What is the total time that the bullet is in contact with theboard?
2 s
(c) What thickness of board (calculated to 0.1 cm) would it take tostop the bullet, assuming that the acceleration through all boardsis the same?
3 cm (a) What is the average acceleration of thebullet through the board?
1 m/s2
(b) What is the total time that the bullet is in contact with theboard?
2 s
(c) What thickness of board (calculated to 0.1 cm) would it take tostop the bullet, assuming that the acceleration through all boardsis the same?
3 cm

Explanation / Answer

(a) Initial speed (u) of the bullet when it touches the board =420 m/s Final speed (v) of the bullet when it emerged from the board =280 m/s Distance (s) traveled = 10.0cm = 0.10m Then the formula for calculating the value of the acceleration(a) of the bullet is                 a = (v2 - u2) / (2s) (b) Formula for calculating the value of the time (t) takenis                  t = (v - u) / a Do all the calculation work.

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