I have the right answer but dont know how to work it. An isolated conducting sph

Question

I have the right answer but dont know how to work it. An isolated conducting sphere has a 11 cm radius. One wire carries a current of 1.000002 0 A into it. Another wire carries a current of 1.000 000 0 Aout of it. How long would it take for the sphere to increase inpotential by 1200 V?
0.00734s
I have the right answer but dont know how to work it. An isolated conducting sphere has a 11 cm radius. One wire carries a current of 1.000002 0 A into it. Another wire carries a current of 1.000 000 0 Aout of it. How long would it take for the sphere to increase inpotential by 1200 V?
0.00734s

Explanation / Answer

Radius r = 11 cm = 0.11 m

Potential V = 1200 V

Current in i = 1.000002 A

current out i ' = 1.0 A

we know V = Kq / r

from this charge on sphere q = Vr / K

where K = coulom's constant = 8.99 * 10^ 9 N m ^ 2 / C ^2

Related Questions

Navigate

• Browse (All)
• Browse I
• Subjects

---