Pime Community College-PHY 122-Sua18-SILVA Ch Jump to Summeri8 -SILVA Activities

Question

Pime Community College-PHY 122-Sua18-SILVA Ch Jump to Summeri8 -SILVA Activities and Due Dates > Chapter 23A Homework ore: 84.6% Expand Resources Q ?Feedback x Give Up? 12 of 13 Attempt The index of refraction for a certain type of glass is 1.635 for blue light and 1.601 for red light. When a beam of white light (one that contains all colors) enters a plate of glass from the air at an incidence angle of 35.55e, what is the absolute value of 6, the angle in the glass between blue and red parts of the refracted beams? MacBook Air 4) 5 8 0

Explanation / Answer

Using snell's law for blue ray:

n1*sinA1 = n2*sinA2

n1 = refractive index of air = 1

n2 = refractive index of glass for blue ray = 1.635

A1 = angle of incidence = 35.55 deg

A2 = angle of refraction = ?

sinA2 = (n1/n2)*sinA1

A2 = arcsin[(n1/n2)*sinA1]

using given values,

A2 = arcsin[(1/1.635)*sin(35.55)]

A2 = 20.83 deg

Now for red light,

n1*sinA1 = n3*sinA3

n1 = refractive index of air = 1

n3 = refractive index of glass for red ray = 1.601

A1 = angle of incidence = 35.55 deg

A3 = angle of refraction = ?

sinA3 = (n1/n3)*sinA1

A3 = arcsin[(n1/n3)*sinA1]

using given values,

A3 = arcsin[(1/1.601)*sin(35.5)]

A3 = 21.29 deg

So Angle b/w blue and red ray will be,

Angle = A3 - A2 = 21.29 - 20.83 = 0.46 deg

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