In a belly-flop diving contest, the winner is the diver who makes the biggest splash upon hitting the water. The size of the splash depends not only on the diver's style, but also on the amount of kinetic energy that the diver has. Consider a conest in which each diver jumps from a 3.00-m platform. One diver has a mass of 136 kg and simply steps off the platform. Another diver has a mass of 102 kg and leaps upward from the platform. How high would the second diver have t leap to make a competitive splash?
Explanation / Answer
given the mass of one diver is M = 136 kg the height of the diver is H = 3 m the mass of the another diver is m = 102 kg let the height is h according to the conservation of the energy , kineticenergy of the one diver is equal to the potential energy is K.E = MgH = 136 kg *9.8 m/s2 * 3 m = 3998.4 J similarly the kinetic energy of the another diver is K .E =mgh to make competitive splash these two should beequal mgh = 3998.4 J h = 4m so 4m -3m = 1m is the height he has to leap