One mole of an ideal gas initially at temperature ofTi =0 C undergoes an expansion at a constant pressure ofone atmosphere to four times its original volume.(a) Calculate the new temperature Tf of thegas. (b) Calculate the work done on the gas done on the gas duringexpansion. One mole of an ideal gas initially at temperature ofTi =0 C undergoes an expansion at a constant pressure ofone atmosphere to four times its original volume.(a) Calculate the new temperature Tf of thegas. (b) Calculate the work done on the gas done on the gas duringexpansion.
Explanation / Answer
(a) We have the relationTi/Vi = Tf/Vf Then Tf =(Vf/Vi)Ti = (4)(273K) = 1092K =819oC (b) Work done W =P(Vf -Vi) = nR (Tf -Ti) = (1mol)(8.34J/mol K)(1092K - 273K) = 6830.46J = (4)(273K) = 1092K =819oC (b) Work done W =P(Vf -Vi) = nR (Tf -Ti) = (1mol)(8.34J/mol K)(1092K - 273K) = 6830.46J