Question
Consider two vectors with magnitude F1=98N and F2 =82N, where1 = 316 and 2=188, measured from the positive x- axiswith the counter-clockwise angular direction as positive. What is the magnitude of the resultant vector F,where F= FI +F2. And also find the direction of this resultant vector F asangle in drgrees, with counter-clocwise as the positive angulardirection, between the limits of -180 degrees and + 180degrees. Consider two vectors with magnitude F1=98N and F2 =82N, where1 = 316 and 2=188, measured from the positive x- axiswith the counter-clockwise angular direction as positive. What is the magnitude of the resultant vector F,where F= FI +F2. And also find the direction of this resultant vector F asangle in drgrees, with counter-clocwise as the positive angulardirection, between the limits of -180 degrees and + 180degrees.
Explanation / Answer
Phase difference between F 1 and F 2 is = 1 - 2 = 128 So, magnitude of resulatnt force F = [ F12 + F 2 2 + 2 F 1 F2 cos ] substitue values weget answer (b). Let F makes an angle with F 1 then tan =F 2 sin / [ F 1 + F 2 cos ] subsittue values weget answer