an electron is released from the rest at the negative plate ofa parallel plate c

Question

an electron is released from the rest at the negative plate ofa parallel plate capacitor. the charge per unit area on each plateis =1.80*10-7 c/m2, and the plates areseparated by a distance of 1.2* 10-2  m.
how fast is the electron moving just before it reaches the positiveplate? an electron is released from the rest at the negative plate ofa parallel plate capacitor. the charge per unit area on each plateis =1.80*10-7 c/m2, and the plates areseparated by a distance of 1.2* 10-2  m.
how fast is the electron moving just before it reaches the positiveplate?

Explanation / Answer

Initila velocity u = 0 m / s charge per unit area on each plate is =1.80*10-7 c/m2 separation of the plates d =  1.2* 10-2  m we know electric field E = / where = permitivity of free space = 8.85 * 10-12 C 2 / N m 2 Let Speed of the electron when it reach the positiveplate be v then from the relation v 2 - u 2 =2aS    you find   v  value where a = accleration   = Eq / m            q = charge of elecron = 1.6 * 10 -19 C            m= mass of electron = 9.1 * 10 -31 kg substitue values weget answer

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