ball is tossed from an upper-story window of a building. The ballis given an ini

Question

ball is tossed from an upper-story window of a building. The ballis given an initial velocity of 7.60m/s at an angle of 15.0° below thehorizontal. It strikes the ground 6.00s later. (a) How far horizontally from the base of thebuilding does the ball strike the ground?
1 m
(b) Find the height from which the ball was thrown.
2 m
(c) How long does it take the ball to reach a point 10.0 m belowthe level of launching?
3 s (a) How far horizontally from the base of thebuilding does the ball strike the ground?
1 m
(b) Find the height from which the ball was thrown.
2 m
(c) How long does it take the ball to reach a point 10.0 m belowthe level of launching?
3 s

Explanation / Answer

a) xf = vxi *t    xf = 7.60m/s * cos 15.0o * 6.00s    xf = 44.0m b) yf = vyi * t.5gt2    yf = 7.60m/s * sin 15.0o * 6.00s + .5 * 9.80 m/s2 *(6.00s)2    yf = 188m c) yf = vyi * t.5gt2    10.0m = 7.60 m/s * sin15.0o * t + .5 * 9.80 m/s2 *t2    0 = 4.90t2 +1.97t - 10.0    solve the quadraticformula to get t=1.24s or t=.1.64s    time cannot be negativeso    t=1.24s    0 = 4.90t2 +1.97t - 10.0    solve the quadraticformula to get t=1.24s or t=.1.64s    time cannot be negativeso    t=1.24s

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