Points A and B have electric potentials of251 V and 129 V, respectively. When an
ID: 1737497 • Letter: P
Question
Points A and B have electric potentials of251 V and 129 V, respectively. When anelectron released from rest at point A arrives at pointC its kinetic energy is KA. When theelectron is released from rest at point B, however, itskinetic energy when it reaches point C isKB = 3KA (a) What is the electric potential at point C?(b) What is the kinetic energy KA?
Points A and B have electric potentials of251 V and 129 V, respectively. When anelectron released from rest at point A arrives at pointC its kinetic energy is KA. When theelectron is released from rest at point B, however, itskinetic energy when it reaches point C isKB = 3KA (a) What is the electric potential at point C?
(b) What is the kinetic energy KA?
Explanation / Answer
VA = 251 V, VB = 129 V, q = -1.60*10-19 C KA = q(VA - VC) KB = 3KA = q(VB - VC) solve for KA and VC