As you can see I went wrong when it came to answering, thecharge on the plate ..

Question

As you can see I went wrong when it came to answering, thecharge on the plate ... I used the formula (Q)=C^V After pluggingin my values, (4.80e-12F)(24V), I got Q=11.5e.12C. Which should be11.5pC. Webassign counted it wrong and I really thought I didit correctly. Will someone please help me find myerror.
An air-filled capacitor consists of two parallel plates, eachwith an area of 7.6 cm2, separated by a distance of1.40 mm. If a 24.0 V potential difference is applied to theseplates, calculate the following.

Explanation / Answer

Q = (4.80E-12) (24) = 1.152E-10 C =  115.2 E -12 C =   115.2 pC. decimal or power of 10 error when doingmath.    Method was correct. :)

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