Part A What is the acceleration of the bowling ball,in magnitude and direction,

Question

Part A What is the acceleration of the bowling ball,in magnitude and direction, at this instant?
Part B What is the tension in the rope at thisinstant? What is the acceleration of the bowling ball,in magnitude and direction, at this instant? Part B What is the tension in the rope at thisinstant? A bowling ball weighing 70.7 N is attached to the ceiling by a rope of length3.74 m. The ball is pulled to one side and released; it thenswings back and forth as a pendulum. As the rope swings through thevertical, the speed of the bowling ball is 4.00 m/s. Part A What is the acceleration of the bowling ball,in magnitude and direction, at this instant? Part B What is the tension in the rope at thisinstant?

Explanation / Answer

acceleration a=v2/r a=42/3.74 a=4.28m/s2 Its magnitude is towards the centre. Weight W=mg=70.7 m=70.7/9.8 m=7.21kg The tension T in the rope is T=F=mv2/r T=7.21*42/3.74 T=30.84N

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