A 6.90-kg object is initially moving sothat its x -component of velocity is 6.00
ID: 1739362 • Letter: A
Question
A 6.90-kg object is initially moving sothat its x-component of velocity is 6.00 m/s andy-component of velocity is -2.10m/s. (a) What is the kinetic energy of the object atthis time?1 J
(b) Find the change in kinetic energy of the object it itsvelocity changes so that its new x-component is 8.50 m/sand its new y-component is 5.00 m/s.
2 J (a) What is the kinetic energy of the object atthis time?
1 J
(b) Find the change in kinetic energy of the object it itsvelocity changes so that its new x-component is 8.50 m/sand its new y-component is 5.00 m/s.
2 J
Explanation / Answer
Ek=1/2M*V2, V=squareroot[(6.00)2+(-2.10)2]=6.36m/s Ek=.5*(6.90Kg)*(6.36m/s)2=139.6J (joules,N*m) repeat the process to get your second answer. if you do not understand how i arrived at 6.36m/s, i was using thePythagroean Thereom (pardon spelling),C2=A2+B2 where C=the hypotnuse (our total velocity) A=our x-component B=our y-component