A diverof mass m dropsfrom a board 6m above the water\'ssurface. Neglect air res

Question

A diverof mass m dropsfrom a board 6m above the water'ssurface. Neglect air resistance. speed at 3m above waterssurface=7.67m/s speed as he hits thewater=10.8m/s
Supposethe diver vaults off the springboard, leaving it with an initialspeed of 3.79 m/s upwards. Useenergy conservation to find his speed when he strikes thewater. speed at 3m above waterssurface=7.67m/s speed as he hits thewater=10.8m/s
Supposethe diver vaults off the springboard, leaving it with an initialspeed of 3.79 m/s upwards. Useenergy conservation to find his speed when he strikes thewater.

Explanation / Answer

According to the law of conservation of energy we have (PE+KE)at board=(PE+KE)at surface water mgh1+1/2*mv12=mgh2+1/2*mv22 9.8*6+3.792/2=9.8*0+v2/2 v=11.49m/s 9.8*6+3.792/2=9.8*0+v2/2 v=11.49m/s

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---