Can someone please show me the work, so I canknow what I did wrong. thanks. tens
ID: 1739970 • Letter: C
Question
Can someone please show me the work, so I canknow what I did wrong. thanks. tension in cable 1Your answer differs from the correct answerby 10% to 100%. kN horizontal RF component 2
Your answer differs from the correct answerby 10% to 100%. kN 3---direction---leftright vertical RF component 4
Your answer is within 10% of the correctvalue. This may be due to roundoff error, or you could have amistake in your calculation. Carry out all intermediate results toat least four-digit accuracy to minimize roundoff error. kN 5---direction---upwarddownward
Explanation / Answer
an object is said to be in equlibrium only when thenet external torque must be zero about any axis, so we get = 0 and we choose the axis perpendicular to the pageand passing through the lower and of the boom this gives - (1.15 kN) ((l / 2) cos65o)+ T ((3 / 4)l) - (2 kN) (l cos65o) =0 the tension will be T = ........... N as the net horizontal forces are zero weget Fx = 0 H = T cos25o = ........... as the net vertical forces are zero weget Fy = 0 V = 3.15 kN - T sin25o = ........... = ...........