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Can someone please show me the work, so I canknow what I did wrong. thanks. tens

ID: 1739970 • Letter: C

Question

Can someone please show me the work, so I canknow what I did wrong. thanks. tension in cable 1
Your answer differs from the correct answerby 10% to 100%. kN horizontal RF component 2
Your answer differs from the correct answerby 10% to 100%. kN   3---direction---leftright vertical RF component 4
Your answer is within 10% of the correctvalue. This may be due to roundoff error, or you could have amistake in your calculation. Carry out all intermediate results toat least four-digit accuracy to minimize roundoff error. kN  5---direction---upwarddownward

Explanation / Answer


   an object is said to be in equlibrium only when thenet external torque must be zero about any    axis, so we get    = 0    and we choose the axis perpendicular to the pageand passing through the lower and of the    boom this gives    - (1.15 kN) ((l / 2) cos65o)+ T ((3 / 4)l) - (2 kN) (l cos65o) =0    the tension will be    T = ........... N    as the net horizontal forces are zero weget    Fx = 0    H = T cos25o        = ...........    as the net vertical forces are zero weget    Fy = 0    V = 3.15 kN - T sin25o        = ...........        = ...........