(a) How long does it take the solenoid currentto reach 0.632 times its maximum v

Question

(a) How long does it take the solenoid currentto reach 0.632 times its maximum value?
s

(b) Determine the average back emf caused by the self-inductance ofthe solenoid during this interval. The magnetic field produced bythe solenoid at the location of the coil is one-half as strong asthe field at the center of the solenoid.
V

(c) Determine the average rate of change in magnetic flux througheach turn of the coil during the stated interval.
V

(d) Find the magnitude of the average induced current in thecoil.
A Please work solutions out completely to receivea rating of lifesaver.

Explanation / Answer

(a)    the current in the solenoid reaches    I = 0.632 Imax in the time    t =      = L / R    where    L = o N2 A /a       = .......... H    t = ........ s (b)    the change in thesolenoid current duringthis time is    I = 0.632 Imax - 0         = 0.632 (V /R)         = 0.632 (60 V /R)         = ...........A    back =  L(I / t)             =........ V (c)    B / t =(B) A / t                  = (1 / 2) [o n (I)] A / t                   =.......... V (d)    I = coil /Rcoil      = Ncoil(B / t) / Rcoil      = ......... A

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