Hooke\'s law describes a certain light spring of unstretched length31.0 cm. When

Question

Hooke's law describes a certain light spring of unstretched length31.0 cm. When one end is attached to thetop of a door frame, and a 6.40-kg objectis hung from the other end, the length of the spring is44.00 cm. (a) Find its spring constant. (b) The load and the spring are taken down. Twopeople pull in opposite directions on the ends of the spring, eachwith a force of 190 N. Find the length ofthe spring in this situation. I know that the formula is PEs = (1/2)kx^2 butI am having trouble in figuring out this problem. Anything willhelp. Thank you.
(a) Find its spring constant. (b) The load and the spring are taken down. Twopeople pull in opposite directions on the ends of the spring, eachwith a force of 190 N. Find the length ofthe spring in this situation. I know that the formula is PEs = (1/2)kx^2 butI am having trouble in figuring out this problem. Anything willhelp. Thank you.

Explanation / Answer

F=kx mg=k(0.44-0.31) 6.4*9.8=k(0.44-0.31) k=482.4615N/m If they are pulling on each side then F=kx 190=482.4615*x x=0.393814m As it is pulled on both sides then The total length is L=2*0.39381=0.7876276m Hence we get by it.

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