A capacitor has a potential difference of 500V. The plateswith Q=3uC are 5mm apa

Question

A capacitor has a potential difference of 500V. The plateswith Q=3uC are 5mm apart.
Find:
a) Uniform field between the plates b) Capacitance c) Magnitude of the force on an electron between theplates d) Assuming that the voltage stays constant, what happens to Qif the seperation goes from 5mm to 3mm? A capacitor has a potential difference of 500V. The plateswith Q=3uC are 5mm apart.
Find:
a) Uniform field between the plates b) Capacitance c) Magnitude of the force on an electron between theplates d) Assuming that the voltage stays constant, what happens to Qif the seperation goes from 5mm to 3mm?

Explanation / Answer

(a). electric field E = V / d                              = 500 V / ( 5 * 10 ^ -3 m )                              = 10 ^ 5 V / m (b).Capaciatnce C = Q / V                              = ( 3 * 10 ^ -6 C ) / 500 V (c). Magnitude of the force on an electron between the platesis F = E Q substitue values weget answer

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