A 0.25 kg soccer ball is rolling at 6.0 m/s toward a player. Theplayer kicks the

Question

A 0.25 kg soccer ball is rolling at 6.0 m/s toward a player. Theplayer kicks the ball back in the opposite direction and gives it avelocity of 14 m/s. What is the average force during the interaction if theinteraction lasts 2.0x10-2 seconds? please give step by step instruction with solutioncalculated
A 0.25 kg soccer ball is rolling at 6.0 m/s toward a player. Theplayer kicks the ball back in the opposite direction and gives it avelocity of 14 m/s. What is the average force during the interaction if theinteraction lasts 2.0x10-2 seconds? please give step by step instruction with solutioncalculated

Explanation / Answer

mass m = 0.25 kg initial velocity u = 6 m / s final velocity v = - 14 m / s change in velocity dv = v - u = -20 m / s change in momentum   P = m dv                                     = - 5 kg m / s time t = 0.02 s So, force F = P / t                   = 250 N

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