A block of mass m=12kg is released from rest on africtionless incline of angle =

Question

A block of mass m=12kg is released from rest on africtionless incline of angle =30o. Below theblock is a spring that can be compressed 2.0cm by a forcw of270N. The block momentarily stops when it compresses thespring by 5.5cm.  
What is the speedof the block just as it touches the spring? The solution use the equation: Please explain how length= -.29 A block of mass m=12kg is released from rest on africtionless incline of angle =30o. Below theblock is a spring that can be compressed 2.0cm by a forcw of270N. The block momentarily stops when it compresses thespring by 5.5cm.  
What is the speedof the block just as it touches the spring? The solution use the equation: Please explain how length= -.29

Explanation / Answer

Spring constant of the spring K = force /compression                                                 = 270 N / 2 cm                                                = 270 N / 0.02 m                                                 = 13500 N / m mass of the block m = 12 kg maximum compression A = 5.5 cm = 0.055 m from law of conservation of energy , ( 1/ 2) K A ^ 2 = ( 1/ 2)m v ^ 2 from this the speed of the block just as it touches thespring   v = A [ K / m ]                                                                                              = 1.8447 m / s

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---