Objects with masses of 255 kg and a555 kg are separated by 0.300 m. (a) Find the

Question

Objects with masses of 255 kg and a555 kg are separated by 0.300 m. (a) Find the net gravitational force exerted bythese objects on a 60.0 kg objectplaced midway between them.
1 N
(b) At what position (other than infinitely remote ones) can the60.0 kg object be placed so as toexperience a net force of zero?
2 m from the 555kg mass (a) Find the net gravitational force exerted bythese objects on a 60.0 kg objectplaced midway between them.
1 N
(b) At what position (other than infinitely remote ones) can the60.0 kg object be placed so as toexperience a net force of zero?
2 m from the 555kg mass

Explanation / Answer

Given m = 255 kg           m ' =555 kg separation r = 0.3 m (a). net gravitational force exerted by these objects on a60.0 kg object placed midway betweenthem i.e. f = F + F ' where F = gravitational force at mid point due to 255kg              = G ( 255 kg ) ( 60 kg ) / [ 0.3 m / 2 ] 2 where G = Gravitational constant = 6.67 * 10 ^ -11 N m ^2 / kg ^ 2 substitue values weget F value           F ' =gravitational force at mid point due to 555 kg              = G ( 555 kg ) ( 60 kg ) / [ 0.3 m / 2 ] 2 where G = Gravitational constant = 6.67 * 10 ^ -11 N m ^2 / kg ^ 2 substitue values weget F ' value from this we find    f   value (b). Let at a distance x from the 555 kg the netforce is zero . then force on 60 kg due to 255 kg = force on 60 kg due to 555kg         G ( 255) ( 60) / ( 0.3 - x ) 2 = G ( 555 ) ( 60 ) / x2 from this ( 255) / ( 0.3 - x ) 2= ( 555 ) / x 2 from this   ( 0.3 - x ) 2 / x2 = 255 / 555 solving we get answer where G = Gravitational constant = 6.67 * 10 ^ -11 N m ^2 / kg ^ 2 substitue values weget F value           F ' =gravitational force at mid point due to 555 kg              = G ( 555 kg ) ( 60 kg ) / [ 0.3 m / 2 ] 2 where G = Gravitational constant = 6.67 * 10 ^ -11 N m ^2 / kg ^ 2 substitue values weget F ' value from this we find    f   value (b). Let at a distance x from the 555 kg the netforce is zero . then force on 60 kg due to 255 kg = force on 60 kg due to 555kg         G ( 255) ( 60) / ( 0.3 - x ) 2 = G ( 555 ) ( 60 ) / x2 from this ( 255) / ( 0.3 - x ) 2= ( 555 ) / x 2 from this   ( 0.3 - x ) 2 / x2 = 255 / 555 solving we get answer              = G ( 555 kg ) ( 60 kg ) / [ 0.3 m / 2 ] 2 where G = Gravitational constant = 6.67 * 10 ^ -11 N m ^2 / kg ^ 2 substitue values weget F ' value from this we find    f   value (b). Let at a distance x from the 555 kg the netforce is zero . then force on 60 kg due to 255 kg = force on 60 kg due to 555kg         G ( 255) ( 60) / ( 0.3 - x ) 2 = G ( 555 ) ( 60 ) / x2 from this ( 255) / ( 0.3 - x ) 2= ( 555 ) / x 2 from this   ( 0.3 - x ) 2 / x2 = 255 / 555 solving we get answer from this   ( 0.3 - x ) 2 / x2 = 255 / 555 solving we get answer

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