a proton moving with v= 3E5 m/s perpendicular to a uniformmagnetic field of 0.20

Question

a proton moving with v= 3E5 m/s perpendicular to a uniformmagnetic field of 0.20 T will follow which of the following paths?(q= 1.6E-19 and m=1.67E-27)
A. straight line B. circular pathwith radius of 1.6cm C. circular path with radius 3.1cm --I know the answer is B, but don't know how to solve or whatformula(s) to use! Will rate a proton moving with v= 3E5 m/s perpendicular to a uniformmagnetic field of 0.20 T will follow which of the following paths?(q= 1.6E-19 and m=1.67E-27)
A. straight line B. circular pathwith radius of 1.6cm C. circular path with radius 3.1cm --I know the answer is B, but don't know how to solve or whatformula(s) to use! Will rate

Explanation / Answer

The radius of the circular path is                       r = mv/qB Where v speed of the proton And m is the mass of the proton and q is the charge of theproton , the magnitude of magnetic field B Now substitute all the above values to get the requiredanswer

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