car initially traveling at 30.5 m/sundergoes a constant negative acceleration of

Question

car initially traveling at 30.5 m/sundergoes a constant negative acceleration of magnitude1.70 m/s2 after its brakes areapplied. (a) How many revolutions does each tire makebefore the car comes to a stop, assuming the car does not skid andthe tires have radii of 0.330 m?
1 rev

(b) What is the angular speed of the wheels when the car hastraveled half the total distance?
2 rad/s (a) How many revolutions does each tire makebefore the car comes to a stop, assuming the car does not skid andthe tires have radii of 0.330 m?
1 rev

(b) What is the angular speed of the wheels when the car hastraveled half the total distance?
2 rad/s

Explanation / Answer

initial velocity u = 30.5 m / s final velocity v = 0 m / s acccleration a = 1.7 m / s ^ 2 from the relation v ^ 2 - u ^ 2 = 2 aS   wefind displacement   S = [ v ^ 2 - u ^ 2 ] / 2 a substitue values weget S value (a). radius r = 0.330 m circumference of the tire L = 2 r So, No.of revolutions N = S / L substitue values we get answer (b). from the relation V ^ 2 - u ^ 2 = 2 a ( S / 2)     since distance = S / 2 we find linear speed V   value from this angular speed = V / r substitue values weget answer

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