Two people, each of 70 kg mass, areriding in an elevator. One is standing on the

Question

Two people, each of 70 kg mass, areriding in an elevator. One is standing on the floor. The other ishanging on a rope suspended from the ceiling. Compare the forceFF the floor exerts on thefirst person to the force FRthe rope exerts on the second person. Which statement iscorrect?
FR isless than FF, but they havethe same direction.
They are equaland have the same direction.
FR isgreater than FF, but they havethe same direction.
They are equaland opposite in direction.
FR isgreater than FF, but they haveopposite directions.

Explanation / Answer

F=(2m + m)a = 3ma F= Fd - f + mg Fd= 2mgsin(30)   (I think it is 30 but the pictureis a bit blurry) f= 2mgcos(30) we have 3ma = 2mgsin(30) - 2mgcos(30) + mg 3ma = 2mgsin(30) - 2mgcos(30) + mg 3a = g (2sin(30) - 2cos(30) + 1) a=  g (2sin(30) - 2cos(30) + 1)/3 a= 9.81( 2 sin(30) - 2 x 0.29 cos(3) + 1)/3 a=4.9 m/s Let me know if you have any questions. F=(2m + m)a = 3ma F= Fd - f + mg Fd= 2mgsin(30)   (I think it is 30 but the pictureis a bit blurry) f= 2mgcos(30) we have 3ma = 2mgsin(30) - 2mgcos(30) + mg 3ma = 2mgsin(30) - 2mgcos(30) + mg 3a = g (2sin(30) - 2cos(30) + 1) a=  g (2sin(30) - 2cos(30) + 1)/3 a= 9.81( 2 sin(30) - 2 x 0.29 cos(3) + 1)/3 a=4.9 m/s Let me know if you have any questions.

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