Figure 9-48 gives an overhead view of the path taken by a 0.165kg cue ball as it

Question

Figure 9-48 gives an overhead view of the path taken by a 0.165kg cue ball as it bounces from a rail of a pool table. The ball'sinitial speed is 2.52 m/s, and the angle1 is 62.4°. The bounce reverses they component of the ball's velocity but does not alter thex component. What are (a) angle2 and (b) the magnitudeof the change in the ball's linear momentum? (The fact that theball rolls is irrelevant to the problem.)

Fig. 9-48
Problem 20.

(a)

Number

Units

Chapter 9, Problem 20

Figure 9-48 gives an overhead view of the path taken by a 0.165kg cue ball as it bounces from a rail of a pool table. The ball'sinitial speed is 2.52 m/s, and the angle1 is 62.4°. The bounce reverses they component of the ball's velocity but does not alter thex component. What are (a) angle2 and (b) the magnitudeof the change in the ball's linear momentum? (The fact that theball rolls is irrelevant to the problem.)

Fig. 9-48
Problem 20.

(a)

Number

Units

This answer has no units° (degrees)mkgsm/sm/s^2NJWN/mkg·m/s or N·sN/m^2 or Pakg/m^3gm/s^3times

Explanation / Answer

             Given that the initial speed is U = 2.52 m/s              The angle is 1 = 62.40              mass of the ball is m = 0.165 kg -----------------------------------------------------------------                  mass of the ball is m = 0.165 kg -----------------------------------------------------------------               since there is no external force in y-direction then momentum isconserved .                             m*Usin 1 =  m*Usin 2                  Then 1 = 2 = 62.40                    changein moemntum is P = m*Ucos 2 (-j) - m*Ucos 2 (+j)                                                     =2 m*U cos 2                                                    = ------- kg.m/s (j)          

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