A coin is placed 15.0 cm fromthe axis of a rotating turntable of variable speed.

Question

A coin is placed 15.0 cm fromthe axis of a rotating turntable of variable speed. When the speedof the turntable is slowly increased, the coin remains fixed on theturntable until a rate of 34 rpmis reached, at which point the coin slides off. What is thecoefficient of static friction between the coin and theturntable?
I get .19 = mew of friction forthe answer but the webassign says it's wrong. What formuladid other peeps use? I get .19 = mew of friction forthe answer but the webassign says it's wrong. What formuladid other peeps use?

Explanation / Answer

            Given that the distance between the coin and the axis of rotationis d = 15.0 cm = 0.15 m             The angular velocity is = 34 rpm = ( 34*2 / 60)rad/s = 3.55 rad/s      -------------------------------------------------------------------------------------------------------         If the coin moveson the table without the sliding on the rough horizontalplane                                                                mg >= mr2                                    g >= r2                                       >= r2 / g                                          >=----------                                        g >= r2                                       >= r2 / g                                          >=----------    

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