A wire is 1.1 mlong and 0.94 mm2 in cross-sectional area. It carries a current o

Question

A wire is 1.1 mlong and 0.94 mm2 in cross-sectional area. It carries a current of3.1 A when a 1.9 V potential difference is applied between itsends. Calculate the conductivity of the material of whichthis wire is made.
Dont understand what Im doing wrong? (1.9 * .94 * 10-7) / (3.1 * 1.1 ) = 19230769.23 ohm*m- OR (1.9 *.94 * 10-6) / ( 3.1 * 1.1) = 190912.562 ohm*m- A wire is 1.1 mlong and 0.94 mm2 in cross-sectional area. It carries a current of3.1 A when a 1.9 V potential difference is applied between itsends. Calculate the conductivity of the material of whichthis wire is made.
Dont understand what Im doing wrong? (1.9 * .94 * 10-7) / (3.1 * 1.1 ) = 19230769.23 ohm*m- OR (1.9 *.94 * 10-6) / ( 3.1 * 1.1) = 190912.562 ohm*m-

Explanation / Answer

length L = 1.1 m area of cross section A = 0.94 mm ^ 2                                    = 0.94 * 10 ^ -6 m ^ 2 current i = 3.1 A potential difference V = 1.9 V So, resistance of the wire R = V / i                                           = 0.6129 we know R = L / A from this we find reistivity value So, conductivity of the material of the wire   = 1 /                                                                      = L / R A substitue values weget answer

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