Q5. A motorcycle is moving at 40 m/s when the riderapplies the breaks, giving mo

Question

Q5. A motorcycle is moving at 40 m/s when the riderapplies the breaks, giving motorcycle a constant deceleration. During the 3 s interval immediately after breaking begins,the speed decreases to 15 m/s.
(a). What distance does the motorcycle travel from theinstant breaking begins until the motorcycle stops? Q5. A motorcycle is moving at 40 m/s when the riderapplies the breaks, giving motorcycle a constant deceleration. During the 3 s interval immediately after breaking begins,the speed decreases to 15 m/s.
(a). What distance does the motorcycle travel from theinstant breaking begins until the motorcycle stops?

Explanation / Answer

a = v/t a= (40 - 15)/ 3 a= 8.3 m/s2 S= 0.5at2 Also V= at t= V/a an dnow S= 0.5 a (V/a)2 Also V= at t= V/a an dnow S= 0.5 a (V/a)2 S'= 0.5 (V)2/a ;   S'   is the distance the motorcycletravel from the instant breaking begins until the motorcyclestops S'=0.5 x (40)2 /8.3   S' = 96.4m Than should do it. Please let me know if you have any questions.

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