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Any help would beappreciated!!! It has only been fairly recently that 1.0-Fcapac

ID: 1743694 • Letter: A

Question

Any help would beappreciated!!!
It has only been fairly recently that 1.0-Fcapacitors have been readily available. A typical such capacitorcan withstand up to 5.0 V. To get an idea why it isn't easy to makea 1.0-F capacitor, imagine making a 1.0-Fparallel-plate capacitor using titanium dioxide (= 90.0, breakdown strength 4.00 kV/mm) as the dielectric.(a) Find the minimum thickness of the titanium dioxide such thatthe capacitor can withstand 5.00 V. (b) Find the area of the platesso that the capacitance is 1.0 F. Any help would beappreciated!!!
It has only been fairly recently that 1.0-Fcapacitors have been readily available. A typical such capacitorcan withstand up to 5.0 V. To get an idea why it isn't easy to makea 1.0-F capacitor, imagine making a 1.0-Fparallel-plate capacitor using titanium dioxide (= 90.0, breakdown strength 4.00 kV/mm) as the dielectric.(a) Find the minimum thickness of the titanium dioxide such thatthe capacitor can withstand 5.00 V. (b) Find the area of the platesso that the capacitance is 1.0 F.

Explanation / Answer

. 1.   0 = 8.85E-12Farads/meter 2.   Capacitance =(K)*(0)*(Area)/(distance) 3.   d = distance = (5.0 volts)/[(4000volts/mm)*(1m/1000mm)] = 1.25E-6 meters 4.   Solve '2' for Area:   Area= (Capacitance)*(distance)/[(K)*(0)] 5.   Area = (1.0 Farad)*(1.25E-6meters)/[(90.0)*(8.85E-12 Farads/meter)] 6.   Area = 1.569E+3meters2 .